Math, asked by rakdogra1, 11 months ago

Factorisation of this equation
It's urgent​

Attachments:

Answers

Answered by bhushanbathe
2

Answer:

hey mate here is ur ans..

Step-by-step explanation:

hope it will be helpful.. please mark as brainlist answer..

Attachments:
Answered by dhruv558961
1

Answer:

 {m}^{4}  {n}^{4 }  + 2 {m}^{2 } {n}^{2 } {p}^{2}  +  {p}^{4}

=

 ({m}^{2} {n}^{2})^{2}  + 2{m}^{2} {n}^{2} {p}^{2}  + ( { {p}^{2} })^{2}

=

  ({{m}^{2}  {n}^{2}  +  {p}^{2} })^{2}

=

({{m}^{2}  {n}^{2}  +  {p}^{2} })({{m}^{2}  {n}^{2}  +  {p}^{2} })

it is done with the identity

<marquee>((a+b)^2=a^2+b^2+2ab)</marquee>

Step-by-step explanation:

PLEASE MARK MY ANSWER AS BRAINLIEST.

Similar questions