Question

factorisation of trinomial
$2a {}^{2} + 5a + 7$
​

Answer 1

Answer:

Factoring is the reverse of multiplying. So let’s go in reverse and factor the trinomial x2 + 7x + 10. The individual terms x2, 7x, and 10 share no common factors. So look at rewriting x2 + 7x + 10 as x2 + 5x + 2x + 10.

And, you can group pairs of factors: (x2 + 5x) + (2x + 10)

Factor each pair: x(x + 5) + 2(x + 5)

Then factor out the common factor x + 5: (x + 5)(x + 2)

Here is the same problem done in the form of an example:

Example

Problem

Factor x2 + 7x +10.

x2 + 5x + 2x +10

Rewrite the middle term 7x as 5x + 2x.

x(x + 5) + 2(x + 5)

Group the pairs and factor out the common factor x from the first pair and 2 from the second pair.

(x + 5)(x + 2)

Factor out the common factor

(x + 5).

Answer

(x + 5)(x + 2)

Answer 2

Step-by-step explanation:

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