Question

factorisation of x^2 -4x-12​

Answer 1

$\huge\red {Answer }$

${x}^{2} - 4x - 12$

${x}^{2} + 2x - 6x - 12$

$x(x + 2) - 6(x + 2)$

$(x + 2)(x - 6)$

$<marquee>$hope it helps you.....❤✌

Answer 2

${\red{\underline{\underline{\bold{Given:-}}}}}$

• ${x}^{2} - 4x - 12$

${\green{\underline{\underline{\bold{Solution:-}}}}}$

${x}^{2} - 4x - 12 = 0$

By splitting the middle term

$\implies {x}^{2} -6x + 2x -12 \\ \\</p><p></p><p>\implies x(x-6) + 2(x-6) \\ \\</p><p></p><p>\implies (x-6) (x+2)$

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${\pink{\underline{\underline{\bold{Additional \:Information:-}}}}}$

To factorise a given quadratic expression, we need to solve by the following sequence:-

In the given expression ${x}^{2} - 4x - 12$

a = 1 , b = -4 and c = -12

• Find the product of 1st and last term( a x c). 1x -12 = -12

• Find the factors of -12 in such way that addition or subtraction of that factors is the middle term (-4x)(Splitting of middle term) -6×2 = -12 and -6+2 = -4

• Write the center term using the sum of the two new factors, including the proper signs. ${x}^{2} -6x+2x-12$

• Group the terms to form pairs - the first two terms and the last two terms. Factor each pair by finding common factors. x (x-6)+ 2(2x-6)

• 5) Factor out the shared (common) binomial parenthesis. (x-6) (x+2)