Question

Factorisation of x2-4x-12 is​

Answer 1

Answer:

x² -4x -12

= x² - 6x +2x -12

= x(x-6) +2(x-6)

= (x+2)(x-6)

Answer 2

Question :-

${x}^{2} - 4x - 12 = 0$

What to find out =Roots of the equation?

Solution :-

Factorise by splitting middle term

${x}^{2} - 4x - 12 = 0 \\ \\ {x}^{2} - 6x + 2x - 12 = 0 \\ \\ x(x - 6) + 2(x - 6) = 0 \\ \\ (x - 6)(x + 2) = 0$

Now split it into possible cases

$(x - 6) = 0 \\ \\ (x + 2) = 0$

Hence,

$x_1 = (6) \\ \\ x_2 = ( - 2)$

Extra information :-

• An equation containing a single variable of degree 2. Its general form is ax^2 + bx + c = 0, where x is the variable and a, b, and c are constants (a ≠ 0).