Question

Factorisation of x2+x-12 is :-​

Answer 1

see the answer below

Answer 2

Answer:

$\small{ \color{lime}{{x}^{2} + x - }}$

$\small12 \: can \: be \: factorised \: by \: splitting \\ te \: middle \: term$

$\small{ \pink{{x}^{2} + x - 12}}$

$\small{ \color{red}{sum = 1}}$

$\small{ \orange{product = - 12}}$

$\small{ \color{purple}{ {x}^{2} + x - 12}}$

$\small{ \color{blue} = {x}^{2} + 4x - 3x - 12}$

$\small{ \color{amber}= x(x + 4) - 3(x + 4)}$

$\small{ \color{grey}= x(x + 4)(x - 3)}$

$therefore(x + 4) \: and \: (x - 3) \: are \\ the \: factors \: of \: {x}^{2} + x - 12$