Math, asked by shivangjaiswal188, 3 months ago

factorisation of x²y²+xy+xy²z+yz+x²yz+xz​

Answers

Answered by amitnrw
3

Given :  x²y²+xy+xy²z+yz+x²yz+xz​

To Find : factorise

Solution:

 x²y²+xy+xy²z+yz+x²yz+xz​

=  x²y²+xy   + xy²z+yz   + x²yz+xz​

= xy(xy + 1)  + yz(xy + 1)  + xz(xy  + 1)

=  (xy  + 1) ( xy +  yz + xz)

 x²y²+xy+xy²z+yz+x²yz+xz​ =  (xy  + 1) ( xy +  yz + xz)

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Answered by pulakmath007
2

SOLUTION

TO FACTORISE

x²y² + xy + xy²z + yz + x²yz + xz

EVALUATION

x²y² + xy + xy²z + yz + x²yz + xz

= x²y² + xy²z + x²yz + xy + yz + xz

= xy( xy + yz + xz ) + 1 ( xy + yz + xz )

= ( xy + 1 ) ( xy + yz + xz )

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