Question

factorisation of X3+ 1 is​

Answer 1

Step-by-step explanation:

(x - y)³ = x³ - y³ - 3xy(x - y), or

(x - y)³ + 3xy(x - y) = x³ - y³.

We use x³ - y³ = (x - y)³ + 3xy(x - y) to solve (x³ - 1)-

(x³ - 1³) = (x - 1)³ + 3×x×1(x - 1),

(x³ - 1³) = (x - 1)³ + 3x(x - 1), or (Simplest form)

(x³ - 1) = (x - 1)³ + 3x² - 3x.