Question

Factorisation of Xcube - 23x square + 142x - 120

Answer 1

Answer:-

(x-12)(x-10)(x-1)

Step-by-step explanation:

${x}^{3} - 23 {x}^{2} + 142x - 120 = 0 \\ \\ (x - 1)( {x}^{2} - 22x + 120) = 0 \\ \\ (x - 1)(x - 12)(x - 10) = 0$

NOTE:-

• If (x-a)(x-b)(x-c) = 0 are factors of a equation then roots are a,b,c respectively.