Question

factorisation
$(ax+ by {)}^{2} + (bx - ay {)}^{2}$

Answer 1

Howdy!!

your answer is --

we have ,

${(ax + by)}^{2} + {(bx - ay)}^{2} \\ = {(ax)}^{2} + {(bx)}^{2} + 2abxy + {(bx)}^{2} + {(ay)}^{2} - 2abyx \\ = {(ax)}^{2} + {(bx)}^{2} + {(by)}^{2} + {(ay)}^{2} \\ = {x}^{2} (a + b) + {y}^{2} (a + b) \\ = (a + b)( {x}^{2} + {y}^{2} )$




hope it help you