Question

factorisation using identities 64a^2-121b ^2 copy me likh ke answer bhejo please​

Answer 1

Answer:

$64a^2-121b ^2$

             Rewriting $64a^2=(8a)^2$  and $121b^2=(11b)^2$

$(8a)^2-(11b)^2$

             Using the formula, $x^2-y^2=(x+y)(x-y)$

$(8a-11b)(8a+11b)$