Question

factorisation using identities {(a+b)=a^2 +2ab +b^2} ,, [(a-b) ^2 =a^2 - 2ab +b^2],, (x+a)(x+b) =x^2 +(a+b)x+ab]
Question :p^2 - 6p +8 ​

Answer 1

Answer:

As given in the Question- (a+b)2=a2+2ab+b2

Using this Identity,

(2p+3q)2 =(2p)2+2(2p×3q)+(3q)2

= 4p2+2(6pq)+9q2

= 4p2+12pq+9q2