factorisation: x^2-y^2-6ax+2ay+8a^2
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Answered by
11
Step-by-step explanation:
Given,x2 – y2 – 2(3ax) + 2ay + 9a2 – a2
⇒ x2 – 2(3a)(x) + (3a)2 – (a2 – 2ay + y2)
⇒ (x – 3a)2 – (a – y)2
⇒ (x – 3a – a + y)(x – 3a + a – y)
[Since, from the identity III we know that, (x2 – y2) = (x – y)(x + y)]
⇒ (x – 4a + y)(x – 2a – y)
hope it helps you
please make it brainliest ❤️
Answered by
4
Answer:
Step-by-step explanation:
Given,x2 – y2 – 2(3ax) + 2ay + 9a2 – a2
⇒ x2 – 2(3a)(x) + (3a)2 – (a2 – 2ay + y2)
⇒ (x – 3a)2 – (a – y)2
⇒ (x – 3a – a + y)(x – 3a + a – y)
[Since, from the identity III we know that, (x2 – y2) = (x – y)(x + y)]
⇒ (x – 4a + y)(x – 2a – y)
hope it helps you
please make it brainliest ❤️
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