Question

factorisation x^4-7x^2+1​

Answer 1

Answer:

Factoring  x^4-7x^2+1  

The first term is,  x^4  its coefficient is  1 .

The middle term is,  -7x^2  its coefficient is  -7 .

The last term, "the constant", is  +1  

Step-1 : Multiply the coefficient of the first term by the constant   1 * 1 = 1  

Step-2 : Find two factors of  1  whose sum equals the coefficient of the middle term, which is   -7 .

     -1    +    -1    =    -2  

     1    +    1    =    2  

Observation : No two such factors can be found !!  

Conclusion : Trinomial can not be factored!!

HOPE IT IS CORRECT! :)

Answer 2

My first instinct in factoring is completing the square. x4−7x2+1 naturally becomes (x2−1)2−5x2 or (x2+1)2−9x2. Of the two the latter is a difference of squares and is thus more useful. Thus

x4−7x2+1=(x2+1)2−9x2=(x2+1+3x)(x2+1−3x)

I mean that is virtually unsolvable so....