Question

factorisation
x2 +7√3x + 36​

Answer 1

Here's your answer:

${x}^{2} + 7 \sqrt{3}x + 36$

$= {x}^{2} + 4 \sqrt{3}x + 3 \sqrt{3}x + 36$

$= x(x + 4 \sqrt{3} ) + 3 \sqrt{3} (x + 4 \sqrt{3} )$

$= (x + 3 \sqrt{3})(x + 4 \sqrt{3} )$

Hence,

$x = - 3 \sqrt{3} \: and \: x = - 4 \sqrt{3}$

This is your answer.