Question

factorise (0.99)2 using identity

plz no square or root 2 only 2 ​

Answer 1

Answer:

(0.99)²  

(1 - 0.01)²

================

By Identity,

(a - b)² = a² + b² - 2ab

==================

(1 - 0.01)²

(1)² + (0.01)² -2( 1 × 0.01)

1 + 0.0001 - 0.02

0.9801

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

(0.99)²  

(1 - 0.01)²

================

By Identity,

(a - b)² = a² + b² - 2ab

==================

(1 - 0.01)²

(1)² + (0.01)² -2( 1 × 0.01)

1 + 0.0001 - 0.02

0.9801