Question

factorise 1) 1/16x^2+1/4y^2+1-1/4 x y-y+1/2x​

Answer 1

Step-by-step explanation:

=(1-x^2)×(1-y^2)+4xy

=1×(1-y^2)-x^2(1-y^2) +4xy

=1-y^2-x^2+x^2y^2+4xy

=(1+2xy/x^2y^2)-(y^2+x^2-2xy)

=(1+xy)^2-(x-y)^2

=[(1+xy)+(x-y)]×[(1×xy)-(x-y)]

=[(1+x-y+xy)×(1-x+y+xy)]