Question

factorise: 1) 1-64a^3 , 2) 8a^3 - 27b^3

Answer 1

1-64a³
=1³-(4a)³
using a³-b³=(a-b) (a²+ab+b²)
                   = (1-4a) (1²+1*4a+(4a)²)
                   =(1-4a)(1+4a+16a²)
                    

Answer 2

Hi

Here is your answer

★thanks★

1 - 64a³

= ( 1 )³ - ( 4a )³

= ( 1 - 4a ) ( 1 + 4a + 16a² )

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8a³ - 27b³

= (2a)³ - (3a)³

= ( 2a - 3b ) ( 4a²+ 6ab + 9a² )

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