Question

factorise 1/27 p3 - 8q3

Answer 1

Given;

• 1/27p³ - 8q³
• (1/3p)³ - (2q)³
• (1p/3- 2q) [ (1p/3)² + (2q)² + (1p/3)(2q) ]
• (1p - 6q )/3 × [ 1p²/9 + 4q² + 2pq/3 ]

#answer with quality

#BAL

Answer 2

Answer:

1/27p³ - 8q³ =

( 1/3p - 2q) [ ( 1/3p)²+ (2q)² + 1/3×2.]

( 1/3p-2q) [ 1/9p² + 4q² + 2/3] ( ans)

using identity

a³-b³ = (a-b) (a²+b²+ab)

hope it will help you