Question

factorise 1 - 27 x cube

Answer 1

hope it helps you..........

Answer 2

$<b>$Answer:

$= > 1 - 27 {x}^{3} \\ \\ identity \: used = > \\ = > {a}^{3} - {b}^{3} = (a - b)( {a}^{2} + {b}^{2} + ab) \\ \\ > > {(1)}^{3} - {(3x)}^{3} \\ \\ = > 1 - {27x}^{3} \\ \\ = > (1 - 3x)( {(1)}^{2} + {( - 3x)}^{2} - (1)( - 3x)) \\ \\ = > (1 - 3x)(1 + 9 {x}^{2} + 3x)$

Thanks !