Question

factorise 1-2a-2b-3 (a+b)2

Answer 1

1-2a -2b -3(a+b)² = 1-2(a+b)-3(a+b)² =1- 3(a+ b) +(a+b) -3(a+b)² =1[1-3(a+b)]+(a+b)[1-3(a+b )] =[1-3(a+b)][1+(a+b)] =(1-3a-3b)(1+a+b).

Answer 2

1-2a-2b-3(a+b)^2

1-2(a+b) - 3(a+b)^2

1-3(a+b) + (a+b) - 3(a+b)^2

1((1-3(a+b)) + (a+b) ((1-3(a+b))

((1-3(a+b)) ((1+(a+b))

(1-3a-3b) (1+a+b)