Question

factorise
1+2ab-6a³b³-3a²b²​

Answer 1

Solution

= 1 + 2ab - 6a³b³ - 3a²b²

= 1(1+2ab)-3a²b²(1+2a)

= (1-3a²b²)(1+2ab)

Answer 2

Answer:

1+2ab-6a³b³-3a²b²

Step-by-step explanation:

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