Question

Factorise:-

1+2ab-(a^2+b^2)

Answer 1

$\huge\underline\mathfrak\red{Ans :-}$

$1 + 2ab \: - {a}^{2} \: - {b}^{2} \\ = 1 - ( {a}^{2} - 2ab \: + {b}^{2} ) \\ = 1 - {(a - b)}^{2} \\ = {1}^{2} - {(a - b)}^{2} \: \\ = (1 + a - b)(1 - a + b)$

HOPE IT HELPS ✌

points :-

▒ a² - b² = (a+b) (a-b)

▒ Here a = 1 b = (a-b)

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