Question

FACTORISE 1+2ab-a^2-b^2

Answer 1

may It help you in yoir work

Answer 2

Answer:

$1+2ab-a^2-b^2=(1-a+b)(1+a-b)$

Step-by-step explanation:

Given :$1+2ab-a^2-b^2$

To Find: Factorize

Solution:

$1+2ab-a^2-b^2$

$1-(-2ab+a^2+b^2)$

Using identity : $(x-y)^2=x^2+y^2-2xy$

$1-(a-b)^2$

$1^2-(a-b)^2$

Using identity : $a^2-b^2=(a+b)(a-b)$

$(1-a+b)(1+a-b)$

So, $1+2ab-a^2-b^2=(1-a+b)(1+a-b)$