Question

Factorise :(1/2x − 3y)^3 + (3y − √3z)^3 + (√3z − 1/2x)^3

Answer 1

Given ( x - 2y)3 + (2y - 3z)3 + ( 3z - x)3

Let a =  ( x - 2y), b =(2y - 3z), c= ( 3z - x)

a + b + c = ( x - 2y)+(2y - 3z)+( 3z - x) = 0

Recall that if (a + b + c) = 0 then a3 + b3 + c3 = 3abc

Thus, ( x - 2y)3 + (2y - 3z)3 + ( 3z - x)3 = 3( x - 2y)(2y - 3z)( 3z - x)

Answer 2

Answer:

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