Question

Factorise (1/2x-3y)^3+(3y-√3z)^3+(√3z-1/2x)^3

Answer 1

Given ( x - 2y)3 + (2y - 3z)3 + ( 3z - x)3 Let a = ( x - 2y), b =(2y - 3z), c= ( 3z - x) a + b + c = ( x - 2y)+(2y - 3z)+( 3z - x) = 0 Recall that if (a + b + c) = 0 then a3 + b3 + c3 = 3abc Thus, ( x - 2y)3 + (2y - 3z)3 + ( 3z - x)3 = 3( x - 2y)(2y - 3z)( 3z - x)

Answer 2

Step-by-step explanation:

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