Question

Factorise: 1-2x² please tell me

Answer 1

1-2x^2

(1)^2- (√2x)^2

(1+√2x)(1-√2x)

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Answer 2

$\huge \bold{hey \: there}$

➡1-2x²=0

We have an identity:

a²-b²=(a+b)(a-b)

Now,

➡(1-√2x)(1+√2x)=0

Therefore,x= -1/√2, 1/√2