Factorise ( 1) 3x^2+✓3x-2
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3x² + √3x - 2
________ [GIVEN EQUATION]
• We have to find the factors of it.
_______________________________
3x² + √3x - 2
The above equation is in the form ax² + bx + c.
So.. we have to find the the numbers whose sum is b (√3) and product is c (-6).
3x² + 2√3x - √3x - 2
Sum of (2√3) and (- √3 ) is
2√3 + (- √3) = 2√3 - 1√3 = √3 (2 - 1) = √3
And product of (2√3) and (- √3) is
2√3 × (- √3) = 2 (-3) = - 6
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=> 3x² + 2√3x - √3x - 2
=> √3x √3x + 2√3x - √3x - 2
=> √3x (√3x + 2) - 1 (√3x + 2)
=> (√3x - 1) (√3x + 2)
______________________________
(√3x - 1) and (√3 + 2) are the factors of 3x² + √3x - 2
_________ [ANSWER]
_______________________________
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