FACTORISE 1-3x-3y-4(x+y)^2
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1-3x-3y-4(x+y)²
4-3-3x-3y-4(x+y)²
4(1-(x+y)² )-3(1+x+y)
4(1²-(x+y)² )-3(1+x+y)
4{(1-x-y)(1+x+y)}-3(1+x+y)
(1+x+y) {4(1-x-y)-3}
(1+x+y) {4-4x-4y-3)
⇒ (1+x+y) (1-4x-4y) ....
Anonymous:
M Mjak Kar rhe hu
Answered by
5
1-3x-3y-4(x+y)²
=4-3-3x-3y-4(x+y)²
=4(1-(x+y)² )-3(1+x+y)
=4(1²-(x+y)² )-3(1+x+y)
=4{(1-x-y)(1+x+y)}-3(1+x+y)
=(1+x+y) {4(1-x-y)-3}
=(1+x+y) {4-4x-4y-3)
= (1+x+y) (1-4x-4y)
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