Factorise 1 - 3x-3y-4(x+y)square
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Answered by
15
1-3(x+y)-4(x+y)^2
=1+(x+y)-4(x+y)-4(x+y)^2
=1[1+(x+y)] -4(x+y)[1+(x+y)]
=[1+(x+y)]{1-4(x+y)}
=(1+x+y)(1-4x-4y)
=1+(x+y)-4(x+y)-4(x+y)^2
=1[1+(x+y)] -4(x+y)[1+(x+y)]
=[1+(x+y)]{1-4(x+y)}
=(1+x+y)(1-4x-4y)
Answered by
2
1-3(x+y)-4(x+y)^2
=1+(x+y)-4(x+y)-4(x+y)^2
=1[1+(x+y)] -4(x+y)[1+(x+y)]
=[1+(x+y)]{1-4(x+y)}
=(1+x+y)(1-4x-4y)
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