factorise 1-3x square
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1/3x^2-8/x
=1/3x(x^3-8*3)
Now by using the formula a^3-b^3=(a-b)(a^2+ab+b^2)
So the cube root of 24 is 2*3^1/3
1/3x(x-2*3^1/3)(x^2+2*3^1/3x+2*3^2/3x)
Answered by
0
(1-3x)² [using (a-b)²=a²+b²-2ab]
=> 1²+(3x)²-2×1×3x
=>1+9x²-6x
hope it will help you.
please mark it as brainliest.
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