Question

factorise :
➡️1/3x²-2x-9
please do it correctly ​

Answer 1

Its the answer....

Hope it helped.....

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Answer 2

$</p><p></p><p></p><p>\rightarrow \quad \frac{1}{3}x^{2} - 2x - 9 </p><p></p><p>\\</p><p></p><p>\\</p><p></p><p>\rightarrow \quad \frac{1}{\cancel{3}} \times \cancel{3} \times x^{2} - 2 \times 3 \times x - 9 \times 3 </p><p></p><p>\\ \\</p><p></p><p>\rightarrow \quad x^{2} - 6x - 27 \\ \\ </p><p></p><p>\rightarrow \quad x^{2} - 9x + 3x - 27 \\ \\</p><p></p><p>\rightarrow \quad x(x - 9) + 3( x - 9) \\ \\</p><p></p><p>\rightarrow \quad (x - 9)(x + 3) \\ \\</p><p></p><p>$

Therefore, Zeroes are 9 and -3