Question

Factorise : (1+3y)^2 +(9y^2 - 1)​

Answer 1

Answer:

• The factors are 6y and 3y + 1.

Step-by-step explanation:

Given,

• $\tt {(1 + 3y)}^{2} + (9 {y}^{2} - 1)$

To Find,

• The Factors.

Solution,

$:\implies \tt {(1+ 3y)}^{2} + (9 {y}^{2} - 1) \\ \\ \tt [ {(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} ] \: \: ...[I \: \: Identity] \\ \\ :\implies \tt {1}^{2} + 2(1)(3y) + {(3y)}^{2} + 9 {y}^{2} - 1 \\ \\ :\implies \tt 1 + 6y +9 {y}^{2} + 9 {y}^{2} - 1 \\ \\ :\implies \tt 18 {y}^{2} + 6y \\ \\ :\implies \tt (6 {y})(3 y + 1)$

Required Answer,

• The factors are 6y and 3y + 1.

Answer 2

Answer:

• The factors are 6y and 3y+1.