Question

Factorise

1)49a²+4b²+9c²-28ab+12bc-42ac

2)8a³-y³-12x²y+6xy²

Answer 1

here is your answer
$49 {a}^{2} + 4 {b}^{2} + 9 {c}^{2} - 28ab + 12bc - 42ac \\ ( - 7a {)}^{2} + (2 {b)}^{2} + (3c {)}^{2} - 2 \times 7a \times 2b + 2 \times 2b \times 3c - 2 \times 7a \times 3c \\ \\ using \: identity \: {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2ac + 2bc \\ = (a + b + c {)}^{2} \\ \\ = ( - 7a + 2b + 3c {)}^{2} \\ = ( - 7a + 2b + 3c)( - 7a + 2b + 3c)$
hope this helps you
plz mark as brainliest answer plzzzzz

Answer 2

1.(7a-2b-3c) whole Square
sorry friends I don't know how to type Square in my phone