Question

Factorise 1/4x^2+x-3

Answer 1

$\huge\red{Answer\: is}$

$\frac{1}{4} x {}^{2} + x - 3 \\ = x {}^{2} + 4x - 12 \\ = x {}^{2} + 6x - 2x - 12 \\ = x(x + 6) - 2(x + 6) \\ = (x + 6)(x - 2)$
Hope it helps you

Answer 2

Given Equation is (1/4)x^2 + x - 3.

$=> (\frac{1}{4})x^2 + 4x - 12$

$=> (\frac{1}{4})[x^2 + 6x - 2x - 12]$

$=> \frac{1}{4}[x(x + 6) - 2(x + 6)]$

$=> (\frac{1}{4})[(x - 2)(x + 6)]$

Hope it helps!