Question

Factorise:
1) 4x2 +9y2 + 162? + 12xy - 24 yz - 16xz​

Answer 1

Answer:

4x²+9y²+16z²+12xy–24yz–16xz

We can we write the given expression as

=(2x)²+(3y)²+(−4z)²+(2×2x×3y)+(2×3y×−4z)+(2×−4z×2x)

=(2x+3y–4z)²

Identity used:

[a²+b²+c²+2ab+2bc+2ca = (a²+b²+c²)]

=(2x+3y–4z) (2x+3y–4z)

Step-by-step explanation:

hope this will be helpful for you