Question

factorise 1/4y2+y-3​

Answer 1

Answer:

$\frac{1 }{4} {y}^{2} + y - 3 = 0 \\ {y }^{2} + 4y - 12 = 0 \\ {y}^{2} - 2y + 6y - 12 = 0 \\ y(y - 2) + 6(y - 2) = 0 \\ (y + 6)(y - 2) = 0 \\ hence \\ y = - 6 \: and \: 2$