Question

factorise : 1-64a^3-12a+48a^2

Answer 1

The given eq is in tbe form of a^3-b^3-3a^2b+3ab^2
=>1-(4a)^3-3*1*(4a)+3*1(4a)^2
=>(1-4a)^3

Answer 2

Hi friend,

→1-64a³-12a+48a²

=(1)³-(4a)³-3(1)²(4a)+3(1)(4a)²

This is in the form of a³-b³-3a²b+3ab².

So,a³-b³-3a²b+3ab² = (a-b)³

Here,
a=1,b=4a

So,

(1)³-(4a)³-3(1)²(4a)+3(1)(4a)² = (1-4a)³

So,answer is (1-4a)³

★hope it helps★