Question

factorise 1+64x³ tell me please

Answer 1

Hey user

Here is your answer :-

64x^3 + 1

》( 4x )^3 + ( 1 )^3

According to the identity ,

( a + b )^3 = ( a + b )( a^2 + ab + b^2 )

》( 4x + 1 )[ ( 4x )^2 - ( 4x )( 1 ) + ( 1 )^2 ]

》( 4x + 1 )( 16x^2 - 4x + 1 )

Thank you .

Answer 2

hey dude
1+64x^3
=1^3+4x^3
=(4x+1)(16x^2-4x+1)

hope it helps u

i have used the formula a^3+b^3
=(a+b)(a^2+b^-ab)

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