Question

Factorise
1 +64x³
Using suitable property ​

Answer 1

Answer:

${a}^{3} + {b}^{3} = (a + b)( {a}^{2} + {b}^{2} - ab)$

Step-by-step explanation:

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See The Attachment My Friend....

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Answer 2

Given

Factorise

1 +64x³

Using suitable property

Solution

✞ Applying identity :

a³ + b³ = (a - b)(a² - ab + b²)

➠ 1 + 64x³

➠ (1)³ + (4x)³

➠ (1 - 4x) [(1)² - 1*4x + (4x)²]

➠ (1 - 4x) [1 - 4x + 16x²]

Some identities

• (a+b)² = a² + b² +2ab
• (a-b)² = a² + b² - 2ab
• (a+b)³ = a³ + b³ + 3ab(a+b)
• (a-b)³ = a³ -b³ - 3ab(a-b)
• a² - b² = (a+b)(a-b)
• a³ + b³ = (a+b)(a² - ab +b²)
• a³ - b³ = (a-b)(a² + ab + b²)