Math, asked by laltusharma1912, 8 months ago

factorise=1) 6x^2 +17x+5

rupasanfui47: Let p(x)=6x2+17x+5 the term 65 can be written as many terms one would be (±25,±31),(±65,±1),...……....

Let p(3−1)=0 then by factor theorem 3−1 then the other will be;

6x2+17x+5=(2x+5)(3x+1)

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factorise=1) 6x^2 +17x+5​

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factorise=1) 6x^2 +17x+5