Question

Factorise: 1)8(2a+3b)^3-12(2a+3b)^2

Answer 1

Answer:

4(16a3+72a2b+108ab2+54b3−12a2−36ab−27b2)

Step-by-step explanation:

Factor 8(2a+3b)3−12(2a+3b)2

64a3+288a2b+432ab2+216b3−48a2−144ab−108b2

=4(16a3+72a2b+108ab2+54b3−12a2−36ab−27b2)

Answer 2

this is the solution

8(2a+3b)³-12(2a+3b)²

= 4(2a+3b)² x (2(2a+3b)-3)

= 4(2a + 3b)² x (4a+6b-3)