factorise 1/8a³+1/125b³
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Answer:
a^3+b^3 is an identity
Step-by-step explanation:
now
(a+b)(a^2+b^2-ab)
(1/2a)^3+(1/5)^3
=( 0.5+0.2)(1/4+1/25-0.1)
(0.7)(0.25+0.04-0.1)
(0.7)(0.19)
=0.133
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