Question

Factorise :(1)a cube -b cube +1+3ab(2)x cube +1/x cube-2

Answer 1

Let p (x) = x^3 + 13x^2 +32x + 20

Let p (x) = x^3 + 13x^2 +32x + 20Using hit and trial method

Let p (x) = x^3 + 13x^2 +32x + 20Using hit and trial methodx= -1

Let p (x) = x^3 + 13x^2 +32x + 20Using hit and trial methodx= -1p (-1) = -1 + 13 -32 +20

Let p (x) = x^3 + 13x^2 +32x + 20Using hit and trial methodx= -1p (-1) = -1 + 13 -32 +20=-33+ 33

Let p (x) = x^3 + 13x^2 +32x + 20Using hit and trial methodx= -1p (-1) = -1 + 13 -32 +20=-33+ 33= 0

Let p (x) = x^3 + 13x^2 +32x + 20Using hit and trial methodx= -1p (-1) = -1 + 13 -32 +20=-33+ 33= 0So, (x +1 ) is a factor of p (x) [by factor theorem]

Let p (x) = x^3 + 13x^2 +32x + 20Using hit and trial methodx= -1p (-1) = -1 + 13 -32 +20=-33+ 33= 0So, (x +1 ) is a factor of p (x) [by factor theorem]To fing other factors we must divide p (x) by (x+1)

Let p (x) = x^3 + 13x^2 +32x + 20Using hit and trial methodx= -1p (-1) = -1 + 13 -32 +20=-33+ 33= 0So, (x +1 ) is a factor of p (x) [by factor theorem]To fing other factors we must divide p (x) by (x+1)And the other factor found is x^2 +12x + 10

Let p (x) = x^3 + 13x^2 +32x + 20Using hit and trial methodx= -1p (-1) = -1 + 13 -32 +20=-33+ 33= 0So, (x +1 ) is a factor of p (x) [by factor theorem]To fing other factors we must divide p (x) by (x+1)And the other factor found is x^2 +12x + 10Factorising x^2 +12x +20

Let p (x) = x^3 + 13x^2 +32x + 20Using hit and trial methodx= -1p (-1) = -1 + 13 -32 +20=-33+ 33= 0So, (x +1 ) is a factor of p (x) [by factor theorem]To fing other factors we must divide p (x) by (x+1)And the other factor found is x^2 +12x + 10Factorising x^2 +12x +20= x^2 +10x + 2x +20

Let p (x) = x^3 + 13x^2 +32x + 20Using hit and trial methodx= -1p (-1) = -1 + 13 -32 +20=-33+ 33= 0So, (x +1 ) is a factor of p (x) [by factor theorem]To fing other factors we must divide p (x) by (x+1)And the other factor found is x^2 +12x + 10Factorising x^2 +12x +20= x^2 +10x + 2x +20= x (x +10) +2 (x +10)

Let p (x) = x^3 + 13x^2 +32x + 20Using hit and trial methodx= -1p (-1) = -1 + 13 -32 +20=-33+ 33= 0So, (x +1 ) is a factor of p (x) [by factor theorem]To fing other factors we must divide p (x) by (x+1)And the other factor found is x^2 +12x + 10Factorising x^2 +12x +20= x^2 +10x + 2x +20= x (x +10) +2 (x +10)= (x+2)(x+10)

Let p (x) = x^3 + 13x^2 +32x + 20Using hit and trial methodx= -1p (-1) = -1 + 13 -32 +20=-33+ 33= 0So, (x +1 ) is a factor of p (x) [by factor theorem]To fing other factors we must divide p (x) by (x+1)And the other factor found is x^2 +12x + 10Factorising x^2 +12x +20= x^2 +10x + 2x +20= x (x +10) +2 (x +10)= (x+2)(x+10)So, polynomial p (x) would be factorised as (x+2)(x +10)(x+1).

Let p (x) = x^3 + 13x^2 +32x + 20Using hit and trial methodx= -1p (-1) = -1 + 13 -32 +20=-33+ 33= 0So, (x +1 ) is a factor of p (x) [by factor theorem]To fing other factors we must divide p (x) by (x+1)And the other factor found is x^2 +12x + 10Factorising x^2 +12x +20= x^2 +10x + 2x +20= x (x +10) +2 (x +10)= (x+2)(x+10)So, polynomial p (x) would be factorised as (x+2)(x +10)(x+1).Read more on Brainly.in - https://brainly.in/question/16683780#readmore