Question

factorise 1-a2-b2+2ab

Answer 1

1-a2-b2+2ab
= 1-(a2+b2-2ab)
= 1-(a-b)^2
= 1^2-(a-b)^2
= (1 +a-b) (1-a+b) (answer)

Answer 2

Hey dear here is your answer!!!!!

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We have been given the expression:-

= 1 - a² - b² + 2ab

We can re-write it as:-

= 1 - (a² + b² - 2ab)

Using the identity - a² + b² - 2ab = (a - b)²

= 1 - ( a - b )²

Re - write it as:-

= (1)² - ( a - b )²

Using the identity - a² - b² = ( a + b ) ( a - b )

= ( 1 + a - b )( 1 - a + b )

$\large\boxed{\large\boxed{\large\boxed{Solved !}}}}$

❣️⭐ Hope it helps you dear...⭐⭐❣️❣️