Question

Factorise:
1. a3 – 4a2 + 12 – 3a
2. a3x – x4 + a2x2 – ax3
3. y2 + 8zx – 2xy – 4yz
4. 1+a+ac+a2c
5. Xy-pq+qy-p
6. 3+23Z-8Z2

Answer 1

Factorise a³ - 4a² + 12 - 3a = (a + 3)(a - 3)(a - 4)

a³x – x⁴ + a²x² – ax³ = x(a + x)²(a-x)

Step-by-step explanation:

a³ - 4a² + 12 - 3a

= a²(a - 4)  - 3(-4 + a)

=  a²(a - 4)  - 3(a - 4)

= (a² - 3)(a - 4)

= (a + 3)(a - 3)(a - 4)

a³ - 4a² + 12 - 3a = (a + 3)(a - 3)(a - 4)

a³x – x⁴ + a²x² – ax³

=  a³x + a²x²– ax³– x⁴

= a²x(a + x) - x³(a + x)

= (a²x - x³)(a + x)

= x(a² - x²)(a + x)

= x(a + x)(a - x)(a + x)

= x(a + x)²(a-x)

a³x – x⁴ + a²x² – ax³ = x(a + x)²(a-x)

y² + 8zx – 2xy – 4yz

= y(y -  2x) -4z(y - 2x)

= (y - 2x)(y - 4z)

1 + a  + ac + a²c

= 1 + a + ac(1 + a)

= (1 + ac)(1 + a)

3 + 23z - 8z²

= 3 + 24z - z - 8z²

= 3(1 + 8z) - z(1 + 8z)

= (3 - z)(1 + 8z)

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Answer 2

Answer:

do not know what to do gui