Factorise
1-a³-b³-3ab
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35
Of the form
a3+b3+c3+3abc
a=1,b= -a,c= -b
1-a3-b3-3ab=(1-a-b)(1+a2+b2-a+ab-b)
a3+b3+c3+3abc
a=1,b= -a,c= -b
1-a3-b3-3ab=(1-a-b)(1+a2+b2-a+ab-b)
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Write the above answer
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