Question

Factorise 1-(b-c)^2

Answer 1

${1}^{2} - {(b - c)}^{2} \\ using \: {x}^{2} - {y}^{2} = (x + y)(x - y) \\ ( 1 + b - c)(1 - b + c)$

Answer 2

Heya user, Here is your answer ----

$1 - (b - c) {}^{2} \\ = using \: a {}^{2} - {b}^{2} = (a - b)(a + b) \\ = 1 {}^{2} - (b - c) {}^{2} \\ = (1 - (b - c))(1 + (b - c)) \\ = (1 - b + c)(1 + b - c)$
Hope it will help you