Question

Factorise 1 -p²q²
Factorise 1/16-b²
Factorise 50d²-98e²
Factorise 100-(2a-3b)²

Answer 1

Answer:

(-pq) (-pq)

Step-by-step explanation:

1/8b(-b) 2(25d^2-49e^2

Answer 2

Question 1:-

$1 - {p}^{2} {q}^{2}$

$= {1}^{2} - {(pq)}^{2}$

$= (1 + pq)(1 - pq)$

Question 2:-

$\frac{1}{16} - {b}^{2}$

$= ( \frac{1}{4})^{2} - {(b)}^{2}$

$= ( \frac{1}{4} + b)( \frac{1}{4} - b)$

Question 3:-

$50 {d}^{2} - 98 {e}^{2}$

$= 2(25 {d}^{2} - 49 {e}^{2} )$

$= 2((5d)^{2} - (7e)^{2} )$

$= 2(5d + 7e)(5d - 7e)$

Question 4:-

$100 - (2a - 3b)^{2}$

$= {10}^{2} - (2a - 3b)^{2}$

$= (10 + 2a - 3b)(10 - 2a + 3b)$

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