Question

Factorise:
(1) r- 2x -x+2
(ii) x + 13x2+32x+ 20
(i) x - 3x2 - 9x - 5
(iv) 2y3 + y2 - 2y-1
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Answer 1

iii) 2y³ + y² - 2y - 1 = (2y+1)(y+1)(y-1)

Step-by-step explanation:

Factorising 2y³+y²-2y-1

= y²(2y+1)-1(2y+1)

=(2y+1)(y²-1)

=(2y+1)(y+1)(y-1)

By algebraic identity:

a²-b²= (a+b)(a-b)*/

Therefore,

2y³+y²-2y-1 = (2y+1)(y+1)(y-1)