Question

Factorise:- 1-t-6t²​

Answer 1

Step-by-step explanation:

Final result :

(1 - 3t) • (2t + 1)

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "t2" was replaced by "t^2".

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(1 - t) - (2•3t2)

Step 2 :

Step 3 :

Pulling out like terms :

3.1 Pull out like factors :

-6t2 - t + 1 = -1 • (6t2 + t - 1)

Trying to factor by splitting the middle term

3.2 Factoring 6t2 + t - 1

The first term is, 6t2 its coefficient is 6 .

The middle term is, +t its coefficient is 1 .

The last term, "the constant", is -1

Step-1 : Multiply the coefficient of the first term by the constant 6 • -1 = -6

Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is 1 .

-6 + 1 = -5

-3 + 2 = -1

-2 + 3 = 1 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 3

6t2 - 2t + 3t - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

2t • (3t-1)

Add up the last 2 terms, pulling out common factors :

1 • (3t-1)

Step-5 : Add up the four terms of step 4 :

(2t+1) • (3t-1)

Which is the desired factorization

Final result :

(1 - 3t) • (2t + 1)